3y^2/5
3y has an exponent of 2/5.
2007-01-11 05:05:20 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
What does it equal to?
2007-01-11 05:05:44 · update #1
If 3y has an exponent of 2/5, we would write that as (3y)^(2/5).
One rule of exponents is that a^(1/n)=nth root of a. For example, 9^(1/2) = Square root of 9 = 3, and 32^(1/5) = fifth root of 32 = 2.
Another rule of exponents is that a^(bc)=(a^b)^c. For example, 3^6 = 3^(3*2) = (3^3)^2 = 27^2 = 729. In your problem, we should use a=3y, b=2, and c=1/5.
That is, (3y)^(2/5) = [(3y)^2] ^ (1/5) = Fifth root of (3y)^2
= Fifth root of 9y^2.
This could appear in other forms...also, I'm going with what you wrote out in English, rather than the formula you wrote, which are a bit different. (Your formula is equivalent to "three fifths the square of y".)
2007-01-11 05:17:35 · answer #1 · answered by Doc B 6 · 0⤊ 0⤋
I do not know what you are asking, but 3y does not have an exponent of 2/5 as written. If you assume the orig expression is
3y^(2/5),
then y has an exponent 2/5. It could also be interpretted as
3(y^2)/5.
Bozo
2007-01-11 13:12:20 · answer #2 · answered by bozo 4 · 0⤊ 0⤋
It means 3 * the fifth root of y^2.
Or, if you meant (3y)^2/5 it means the fifth root of 9y^2.
2007-01-11 13:13:26 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
(3y)^2/5=(3y)^(.4) = fifth root ((3y)^2)
2007-01-11 13:10:58 · answer #4 · answered by ENA 2 · 0⤊ 0⤋