Math equation please help!?

Question

Step by step please

(1/2p^2q)^3 (2pq^2)^4

You have to simplify it ..sorry

(1/2p^2q)^3 (2pq^2)^4

Answer 1

OK, (ab)ⁿ = aⁿ bⁿ

So, let's separate out each term within parentheses and then evaluate them, and then we'll combine like terms:

(1/2)^3 * (p^2)^3 * (q)^3 * (2)^4 * (p) ^4 * (q^2) ^4

(pª)ⁿ = pªⁿ. I guess this doesn't come out well. (p^a)^n = p^(an)

1/8 * p^6 * q^3 * 16 * p^4 * q^8

pª * pⁿ = p^ (a+n). This either (p^a) * (p^n) = p^(a+n)

2 * p^10 * q^11

that's it. Remove the *s and such. I was just using them to make it more clear.

Answer 2

this is not an equation, it is an expression. In order for it to be an equation, it needs to be set equal to something. You also need to add parenthesis because there is some ambiguity without them.

(.5p^(2q))^3 * (2p(q^2))^4

distribute exponents:
(.5^3 * p^(3*2q)) * (2^4 * p^ (q^2)^4)

.125p^(6q) * (16 (p^ (q^2)^4))

Answer 3

I don't know what do you wanna do with this expression, but simplifying it, gives:

(1/(2p^2q))^3 (2pq^2)^4 =

(1/8(p^6q)) x (32(p^4)(q^8)) =

4. (p^(4-6q)). (q^8)

Right!?!?

Answer 4

(1/2p^2q)^3 (2pq^2)^4
(1/8*p^6q^3*16p^4q^8
2p^10q^11

Answer 5

not an eqation because the = , < or > is missing

there is nothing you can do with this expression

Answer 6

where is the "=" sign? equations have this sign. you have given an "expression"