Please help me with this problem!?

Question

Choose three integers a, b, and c. (Negative numbers are welcome.) Now use a, be, and c to create a trinomial ax2 + bx + c. Can you factor this trinomial? How would you create a trinomial that will factor?

Answer 1

well....pick nice numbers...its easiest to factor a trinomial with leading coefficent (the stuff infront of the x^2 term) of 1. so let a be 1

now pick a value for b...any value, but its easiest to find a value c if b is even...so lets let b be 6 (but any value will do)

now we want to make a perfect square trinomial...so to do this, take your middle term (b=6) and divide it in half, then square it to get c...so 6/2 (dividing in half)=3, now square it (3^2)=9 , so c=9

no plug those in

x^2 + 6x + 9 is your trinomial, it will factor

it factors to (x+3)(x+3)

it factors to half of the middle term (6), or the root of the constat term (9) because its a square trinomial. This is the easiest way to do this.

good luck

hope this helps
matttlocke

Answer 2

Choose a, b, and c such that (b^2 - 4ac) >= 0. If that is so, then the quadratic formula gives real roots, and hence the factors of ax^2 + bx + c

HTH

Charles

Answer 3

Well, first off, that is a binomial, not a trinomial. Trinomial equations have x³ (x-cubed) in them. There are a lot of binomial equations that are solvable for nubmers a, b, and c. The quadratic formula gives you the answer:

-b ± √(b² - 4ac)
----------------------
        2a

Answer 4

b^2 - 4ac >=0
this means the trinomial has radicals, let's say m and n
then the factors would be
a(x-m)(x-n)=0 (i think)