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Let R = {x,t }, S = {q,t,y }, and T = {t,p,y,v,x },

1.) y ∈ S ∩ T?

2.) x ∈ S ∩ T?

What does this actually mean? Is Y the element of S and intersects T? an or The elements of S intersect T? if so #1 is False, and #2 is True... Could someone give clarification. I am not understanding my book.

2007-01-11 04:03:26 · 5 answers · asked by C 2 in Science & Mathematics Mathematics

5 answers

umm, i can help you with this...but if you could tell me how you got the contained in and interesection symbols i would appreciate it

ok...we are told that R is the set of elements x and t
and we are told S is the set of elements q, t, and y
and T is the set of elements t,p,y,v, and x

so part 1 asks
is y contained in the intersection of S and T, in other words is y in both S and T, it is, so its true

in part 2, we are asked is x contained in the intersection fo S and T, well that asks is x in both set S and set T, its not, so x is not in the intersection, so its false

hope this helps
matttlocke

2007-01-11 05:00:46 · answer #1 · answered by matttlocke 4 · 0 0

This means-- is y an element of the intersection of S and T. Since the intersection of S and T has the elements of S that are also elements of T, the intersection of S and T is {t,y}. y is an element of that intersection. Since x is only in T, it's not in the intersection of S and T.

So, #1 is true, #2 is false.

2007-01-11 12:09:58 · answer #2 · answered by wherearethetacos 3 · 0 0

1) y ∈ S ∩ T just means that

y is an element of S *and* y is an element of T. As you can see, it's true (looking at the sets S and T).

2) x ∈ S ∩ T means

x is an element of S *and* x is an element of T. Although x is an element of S, x is NOT an element of T, rendering the statement false.

If we wanted to, we can assign S ∩ T to a set which we can name B. Then, S ∩ T are the elements common to both, and

S ∩ T = {t, y}

2007-01-11 12:17:41 · answer #3 · answered by Puggy 7 · 0 0

S ∩ T means "all members that S and T have in common".

(Intersection (∩) is a binary operation on two sets, and the result is itself a set.)

Therefore, S ∩ T is the set { t, y }

1) Yes, y is a member of the set S ∩ T = { t, y }

2) No, x is not a member of the set S ∩ T = { t, y }

2007-01-11 12:13:25 · answer #4 · answered by Jim Burnell 6 · 0 0

∩ means the operation which denotes the set having elements common to S and T

Now figure it out.

2007-01-11 12:19:24 · answer #5 · answered by ag_iitkgp 7 · 0 0

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