2007-01-11 04:01:37 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
0 0 0 0 would be one combination
0 0 0 1 would be the 2nd.
How many total and how to calculate this?
2007-01-11 04:04:14 · update #1
4 slots, 10 digits for each slot.
10 *10 *10 *10 = 10000
If you couldn't have any repeats then it would be:
10 * 9 * 8 * 7 = 5040
This is all done with the "multiplication rule". Just multiply the number of possibility for each slot by each other to get the total number of possibilities.
2007-01-11 04:11:41 · answer #1 · answered by Mike J 3 · 1⤊ 0⤋
if you are using all digits 1-9 AND 0 then you are using 10 digits.
multiply that by the power of how many in the set.
for example:
If you were using letters, there are 26 letters in the alphabet. For a 2 letter combination it would be 26²...for a 3 letter combination it would be 26³ and so on.
10^4 is your answer or 10000
if you are only using 1-9 then it would be 9^4 or 9x9x9x9
2007-01-11 12:15:31 · answer #2 · answered by Chris S 2 · 0⤊ 0⤋
10 X 10 X 10 X 10 is how you would calculate it, so that's 10,000 Note that this would lead to 0001 being counted seperately from 1000, etc.
Each placeholder can have 1 of 10 different digits. Your example expressly allowed for leading zeros.
2007-01-11 12:04:54 · answer #3 · answered by Anonymous · 1⤊ 1⤋
The answer is 10x10x10x10=10,000 possibilities.
There is a possible 10 in the first spot, 10 in the second etc.
2007-01-11 12:07:02 · answer #4 · answered by John G 4 · 1⤊ 0⤋
10000
2007-01-11 12:19:12 · answer #5 · answered by ag_iitkgp 7 · 0⤊ 0⤋
Besides all of the 10x10x10...blah blah blah....think a minute.
You start at 0000, that's one. You can only go from 0001 to 9999...sooooo 10,000 would be the answer.
2007-01-11 12:10:22 · answer #6 · answered by Anonymous · 1⤊ 0⤋