Solve using the addition method:4x+5y=10 and then under that -12x=15y-30?

Answer 1

1. 4x+5y = 10
2. -12x -15y = -30

Multiply the second equation by 1/3.
You get -4x -5y = -10, which we will call equation 3.

Add equations 1 and 3 together
4x+5y = 10
-4x -5y = -10

0x +0y = 0

If you look closely, you will see that the second one is just a multiple of the first one...so they are the same line.

Answer 2

4x+5y=10 <-- Eq 1
-12x=15y-30 <-- Eq 2
-12x -15 y = -30 <-- Eq 3 [Rearrange EQ 2}
Multiply 1st equation by 3 getting:
12x + 15y = 30 <-- Eq 4
Add Eq 3 and Eq 4 getting :
0+0=0
Thus the two equations 1 and 2 represent the same straight line and there is no solution.

Answer 3

2x + 3y = 13 <--Multiply this equation with information from (-2) supplying you with -4x + -6y = -26 I I I <--Then upload immediately down, supplying you with 4x + 5y = 22 I I I 0 + (-y) = -4 <---Multiply each and each and every side with information from (-a million) supplying you with y = 4 <---Plug this cost for y into both equation to unravel for x 2x + 3(4) = 13 4x + 5(4) = 22 So the answer set is (a million/2, 4) 2x + 12 = 13 4x + 20 = 22 it is the point the position both strains 2x = a million 4x = 2 intersect. x = a million/2 x = a million/2 similar with the subsequent one. The trick is to make between the variables cancel out. -3x + y = 7 in this one, it is least confusing to multiply the first equation with information from 2, because -2y + 2y is 0 obviously. 6x - 2y = -14 So, then you get -6x + 2y = 14 I I I 6x - 2y = -14 yet wait, each and everything canceled out! 0 = 0 it really is because in case you look heavily, you'll discover they are the same equation. so as which skill there is purely one line, and for this reason a limiteless type of recommendations exist.

Answer 4

0=0

You multiply by 3 in the top
(3) 4x-5y=10
so it ends up being 12x-5y=30
so 12x-15y=30
-12x+15y= -30
They end up cancelling each other out.
then your answer is 0=0 There is no solution

Answer 5

4x+5y=10.......1
-12x=15y-30.....2
from eqn. 1
12x=3[10-5y]
-12x=3[5y-10]....3
from 2&3
15y-30=15y-30
solution is not possible
we need on e more equation.
the seciond eqn given is
the same as the first.

Answer 6

when you x and y to the same side in eq 15y-30=-12x....you get 12x+15y=30...now when you add the two equations....you get 16x+20y=40....When you simplify that...you get 4x+5y=10 which is your answer...

Answer 7

these are dependent equations.They do not solutions.
proof:-
4x+5y=10.................1
12x+15y=30..................2

multiplying by '3'in 1 and 1 in '2'
12x+15y=30
12x+15y=30
- - -
0=0
no solution

Answer 8

To solve this you need two equations and in fact you have only one, just stated in a different form.

Answer 9

No solution,