When plotted on the rectangular coordinate system in which quadrant would the following point be located for this polar coordinate? (-3, 3pi/4).
Any help would be appreciated.. I just don't know how to set these types of problems up.Thanks so much.
2007-01-11 02:23:57 · 6 answers · asked by Matthew B 2 in Science & Mathematics ➔ Mathematics
The co-ordinates you have given seem to be in the polar form of (r,θ).
The given co-ordinates are (-3, 3π/4)
Our θ in terms of degrees is 3 * 180/4 = 135 degrees,
which brings us to the second quadrant.
Our r is -3,
we now have to trace a line of -3 units along the same angle, which will take us to the quadrant which is diagonally opposite to the 2nd quadrant - the 4th quadrant.
2007-01-11 03:49:50 · answer #1 · answered by Preety 2 · 0⤊ 0⤋
Well, 3pi/4 is 135 degrees so the terminal side of the angle lies in quadrant 2. But since r is negative you must extend the terminal side of this angle backward through the pole, placing it in quadrant 4.
To plot a point take the polar axis as the initial side of the angle, lay off the vectorial angle counterclockwise if positive or clockwise if negative, then measure off the radius vector on the terminal side of the angle if r is positive or on the terminal side extended backward through the pole if r is negative.
Hope this helps.
2007-01-11 10:56:40 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
So first think of the angle 3pi/4. This is equivalent to 135 degrees, and we need to measure the angle anti-clockwise from the positive x-axis. Therefore, a positive distance from the origin at this angle would be in the second quadrant.
However, your distance is negative which means you have measure 3 units in the opposite direction, so you will end up in the fourth quadrant.
Draw yourself a little picture!
2007-01-11 10:30:16 · answer #3 · answered by _Jess_ 4 · 1⤊ 0⤋
First figure out where the angle lies:
- 0 & 2pi are the positive x-asis
- pi/2 is the positive y-axis
- pi is the negative x-axis
- 3pi/2 is the negative y-axis
Your angle is 3pi/4 which would lie in the second quadrant. HOWEVER, your radius is negative, so this would flip you over to the fourth quadrant.
2007-01-11 10:29:35 · answer #4 · answered by Dave 6 · 1⤊ 0⤋
that's in quadrant 2. on a rectangualr coordinate plane, the (+,+) quadrant is 1. then count the quadrants moving counterclockwise.
2007-01-11 10:29:13 · answer #5 · answered by eriq p 4 · 0⤊ 3⤋
(-3, 3pi/4) = (3, 3pi/4+pi) = (3, 7pi/4) which is in Quad IV
2007-01-11 10:30:08 · answer #6 · answered by Professor Maddie 4 · 1⤊ 0⤋