Dont sit there wasting your time solving this puzzle
only a genius can get the answer to this
so try only if you have got that maths talent in you !!!!
best of luck
find the value of :
lim x tends to 0 [ 1 - (cos x)^3 ] / [ sin 2x ]
2007-01-10 23:21:08 · 4 answers · asked by wp1_wp1 1 in Science & Mathematics ➔ Mathematics
i am in my first year of college
ie completed 10yrs of school and now just in college by the way
2007-01-10 23:31:37 · update #1
so why post it if you don't think anyone can answer it.
2007-01-10 23:37:44 · answer #1 · answered by pnybt 4 · 0⤊ 0⤋
This is a limit that is of (0/0) so we can apply the de Hospital
rule Thas you can differentiate the fraction
It means that the limit is
limit x tends to 0 (cos^2 x)*sinx/ 2cosx2x
That is equal to zero
2007-01-11 07:33:31 · answer #2 · answered by Ge_Magi70 1 · 1⤊ 0⤋
0/0
according to Hospital rule
take derivative of numerator and denominator
(0+3sinx(cosx)^2)/ (2cos2x)
for x=0
0/(2.1)=0/2=0
2007-01-11 07:50:37 · answer #3 · answered by iyiogrenci 6 · 1⤊ 0⤋
what the heck????????????? who can actually do that? i mean i am really good at math, nt that i am a nerd, actually i am sorta popular, but i mean, what grade are you in? that is RIDICULOUS.
2007-01-11 07:29:53 · answer #4 · answered by mellisa 1 · 0⤊ 0⤋