who can proof that? 1=0?
can you?
go ahead
2007-01-10 17:38:26 · 13 answers · asked by Jafar helper!!! 2 in Science & Mathematics ➔ Mathematics
There is no proof that 1 = 0. Every other proof on this page contains mistakes that falsify them.
If you can prove that 1=0, that means 1=2, 2=3, 3=4, etc, and all the numbers in the entire world are all equal, then we will all be dead.
So stop wasting time.
2007-01-10 18:40:57 · answer #1 · answered by The Answerer 3 · 0⤊ 1⤋
1 - 1 = 0
2007-01-11 01:43:11 · answer #2 · answered by ruged hustlah 2 · 1⤊ 0⤋
There is no 0, there is a concept of 0, but it is just that a concept that is agreed upon to display a digit. A digit has an order, so any digiit has an equation. Therefore 0=1 digit.
Now we have something that we can agree on and work with.
0 is a digit, a numerical data point. 1=0 is meaning 1 is equal to 0 because both are 1 digit. 11=22 because both are two digits. But that is sloppy.
1=0 as one Digit. 0 is 1 digit, 1 is one digit, so 1=0.
2007-01-11 01:56:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
1 mod 1 = 0
2007-01-11 03:21:40 · answer #4 · answered by gjmb1960 7 · 0⤊ 0⤋
Here is the false "proof" that 1 = 0
Let x = 1 and y = 1.
It follows that x = y.
If we square both sides of x = y, we get x^2 = y^2.
If we multiply both sides of x = y by y, we get xy = y^2
x^2 = y^2 implies x^2 - y^2 = 0.
xy = y^2 implies xy - y^2 = 0
Since these are both equal to 0, we can equate them.
x^2 - y^2 = xy - y^2
Factor both sides,
(x - y) (x + y) = y(x - y)
Note the (x - y) on the left hand side and the right hand side. Divide both sides by (x - y) to cancel them.
x + y = y
Plugging our original values back in (that is, x = 1 and y = 1)
1 + 1 = 1
2 = 1
Subtract both sides by 1, and we get
1 = 0
2007-01-11 01:53:49 · answer #5 · answered by Puggy 7 · 0⤊ 0⤋
because 1 = 0, then
0=1, then 1 = 1
2007-01-11 01:47:27 · answer #6 · answered by BryanB 4 · 0⤊ 0⤋
1! = 0!
so cancelling the !, we get 1=0
2007-01-11 02:29:46 · answer #7 · answered by Phineas Bogg 6 · 0⤊ 0⤋
Let x = 1
Let y = 0
Then x+y =1
Multiply both sides by x-y getting:
x^2-y^2 = x - y
Transpose getting:
x^2-x = y^2-y
Add 1/4 to each side to complete the square getting:
x^2-x+1/4 = y^2- y +1/4
(x-1/2)^2 = (y^2-1/2)^2
Take sqrt of both sides getting:
x-1/2=y/1/2
Add 1/2 to both sides getting
x = y
So 1 = 0
Can you find the error?
2007-01-11 01:50:36 · answer #8 · answered by ironduke8159 7 · 0⤊ 0⤋
Yes I can.
How many 'O' (zeros) do You see here ?
=1,
=2
or
=3?
Insert answer here:
And if You don't believe Me then just remember that the CIA have satellite photos to prove it too!
2007-01-11 01:47:13 · answer #9 · answered by Ashleigh 7 · 0⤊ 0⤋
OK if you are going to be like that, then it is true if you round both numbers to the tens position.
2007-01-11 01:56:17 · answer #10 · answered by J C 5 · 0⤊ 0⤋