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is my cal. correct?
SoL= 299,792,458m/s
1furlongs= 201.168m
201.168 / 299,792,448 = 6 x 10^-7 sec/furlongs

SoL= 1,079,252,848.8km/hour
1fortnight=14days
24h=1day
1,079,252,848.8 x 14 x 24 = 3.6 x 10^11 km/fortnight

2007-01-10 15:47:04 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

I think you may misunderstand the question. I read your question as asking what is the speed written as furlongs/fortnight, not two seperate questions.

2007-01-10 15:55:15 · answer #1 · answered by math_ninja 3 · 0 0

Google says no.

http://www.google.com/search?sourceid=navclient&aq=t&ie=UTF-8&rls=DELA,DELA:2005-51,DELA:en&q=speed+of+light+in+furlongs+per+fortnight

the speed of light = 1.8026175 × 10^12 furlongs per fortnight

Here's how I'd do it using dimensional analysis:

299,792,458 meters/sec x (1 furlong/201.168 meters) x (60 sec/1 min) x (60 min/1 hour) x (24 hours/1 day) x (14 days/1 fortnight)

Write it out on a piece of paper. Notice how all the units cancel each other, leaving furlongs on top and fortnights on bottom?

= (299,792,458 x 60 x 60 x 24 x 14)/(201.168)
= 1,802,617,499,785 furlongs / fortnight

Dimensional analysis rocks.

2007-01-10 23:53:00 · answer #2 · answered by Jim Burnell 6 · 0 0

An easy way to check is to type: "c in furlongs/fortnight" into Google; according to Google calculator the answer is 1.8x10^12 furlongs/fortnight.

You can also type "c in furlongs/s" or "c in km/fortnight".

2007-01-10 23:53:00 · answer #3 · answered by rozinante 3 · 0 0

c ≈ (186,282.397 mi/sec)(8 furlongs/mile)(3600 sec/hr)(24 hr/da)(14 da/fortnight)
c ≈ 1,802,617,499,289.6 furlongs/fortnight
c ≈ 1.802617*10^12 furlongs/fortnight

1/c = 1/186,282.397*8 = 6.701242*10-7 sec/furlong

c = (299,792,458 m/s)(1 km/1,000 m)(3600 s/hr)(24 hr/da)(14 da/fortnight
c = 3.626290*10^11 km/fortnight

2007-01-11 00:26:52 · answer #4 · answered by Helmut 7 · 0 0

According to Google calculator, the answer is: 1.8026175 × 10^12

2007-01-10 23:56:06 · answer #5 · answered by electra 1 · 0 0

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