how do you graph a system of equations?

Question

4x+y=2
how would i graph this, please explain

Answer 1

I would put it into y = mx + b form so that I had the slope (m) and the y-intercept (b).

y = -4x + 2 gives us a slope of -4 and a y int of 2. So start at 2 on the y axis and put a point there then go down four and right 1 to get the next point, repeat and then connect the dots.

You could also do this by intercepts:

x intercept ---let y=0 and you get (0.5, 0)
y intercept----let x = 0 and you get (0,2)
Plot the points connect the dots and extend the line!

Answer 2

that isn't a system of equation... that's a single equation, a system of equations have two or more equations

there's a couple ways to graph that.. i like slope intercept
y= mx + b
where m is the slope, and b is the y-intercept

for ur equation, move the 4x over to get

y= -4x + 2

to graph, go on teh y-axis, and count up 2 units, then place a dot

then count one x unit to the right, and 4 y units down from the first dot, and draw another dot

connect your dots, adn there's your line

Answer 3

Well since it is linear solve for the intercepts and then draw a line between them

4x+y = 0
So, when y = 0
x = 0
then solve for another point,
when y = 1, x= -.25

So have 2 points (0,0) and (-.25,1) Plot these and draw a line