2007-01-10 14:05:56 · 3 answers · asked by AQ 1 in Science & Mathematics ➔ Chemistry
You find the oxidation number of the metal by determining the oxidation number of everything that's bonded to that metal.
Examples:
CuSO(4)
SO(4) has an oxidation number of (-2)
Therefore, CU has an oxidation number of (+2)
This is Copper (II) sulfate
Fe(2)O(3)
Each of the oxygen's has an oxidation number of (-2), so their total contribution is (-6)
So, both Fe's have to even out that charge.... and there are two of them, so (+6)/2=3.
This is Iron (III) oxide.
If this isn't clear please let me know.
2007-01-10 14:17:23 · answer #1 · answered by Jess4352 5 · 2⤊ 1⤋
All of the transition metals have at least the S orbital electrons available. If there is no other information available, I would suggest using +2.
2007-01-10 14:12:36 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋
Transition metals can have different charges. For example, the difference between molecules with ferric and ferrous atoms is the charge on the iron atom.
2007-01-10 14:14:07 · answer #3 · answered by CJ M 2 · 0⤊ 0⤋