For absolute values in inequalities, you're going to have two cases:
1) |x| < a (for some positive value a).
In this case, the inequality converts to x < a AND x > -a, or, quite simply, -a < x < a.
2) |x| > a (for some positive value a).
In this case, it is an OR; that is, this translates into
x > a OR x < -a.
Obviously, in our case, we have the less than sign, so we have the AND.
|4 - b| < 4 - b
By the definition above, this becomes
4 - b < 4 - b AND 4 - b > -(4 - b)
Solving the first inequality, we get
4 - b < 4 - b {adding b to both sides,}
4 < 4, which is a false statement.
Therefore, the inequality has no solution.
2007-01-10 13:48:01
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answer #1
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answered by Puggy 7
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The absolute value of 4 - b is less that 4 - b. The absolute value cannot be less than the number. The opposite is possible. But this value of b is an empty set..
2007-01-10 13:49:49
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answer #2
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answered by a simple man 6
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I consistently thought Algebra replaced into plenty much less stressful than Stats yet howdy, diverse strokes for various individuals. seems such as you have a ingredient for Stats (based on your grades.) extreme college stat could desire to be rather resembling college stat. yet while being lazy or having a terrible instructor replaced into particularly the generic clarification for procuring a C in algebra.............then elect Algebra, it rather is oftentimes much less stressful than Stats. yet no longer on the pre-calc point. like if the path is named "beginner's algebra" or "intermediate algebra" it could be fairly easy. If the coures is named "college algebra" that's a factor of pre-calc and that's complicated.
2016-11-28 03:10:22
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answer #3
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answered by ? 4
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|4-b|< 4-b
This is never true.
The |4-b| = or > 4-b
This can be shown more easily by graphing |4-x| and 4-x on the same coordinate system. You will see that |4-x| = 4-x for x = or < 4 and is > b-4 for all x >4.
2007-01-10 14:14:22
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answer #4
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answered by ironduke8159 7
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use the law of absolute values in her book. there will be an example.
2007-01-10 13:45:24
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answer #5
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answered by Trevor Smith 3
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I do not get it. That problem does not look like it makes sense.
2007-01-10 13:52:33
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answer #6
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answered by Anonymous
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