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Pertaining to my previous question on poisonous pill, I will ask it in a may be clearer way.
Weighing can only be done ONCE, using a digital scale.
All the pills are the same size, same color.
There are 10 bottles with 10 pills in each bottle.
One of the bottles contain a pill that is poisonous.
Non-poisonous pill weigh 10 gram each and poisonous pill weighs 11gram (1 gram heavier than the normal ones).
So how can you find out which bottle has the poisonous pill in it?

2007-01-10 13:36:39 · 7 answers · asked by lwc 2 in Science & Mathematics Chemistry

7 answers

It cannot be done in one weighing.
One would need at least 4 (ceil(log2(total bottles))) weighings to do the proper binary search.
I think the puzzle is that one bottle contains nothing but 11gram poison pills. This way you get an answer by taking 1 pill from bottle 1, 2 pills from bottle 2 etc. And do not take any pills from bottle 10. This way you can deduce the poison bottle from the size of the unit's digit part of the weighing.

2007-01-10 13:54:05 · answer #1 · answered by J C 5 · 0 0

The bottle with the poisonous pill will weigh 101 gram.

2007-01-10 21:42:58 · answer #2 · answered by Anonymous · 1 0

I'm not sure if this counts, but put all the bottles on the scales which should equal 101lb. Then remove each bottle one at a time note the weight of the bottles left on the scale. When you remove the bottle that reduces the weight on the scale by 11g, this is the bottle with the poisonous pill. HTH : )

2007-01-10 23:05:14 · answer #3 · answered by Anonymous · 0 0

Obtain 10 lab rats. Force feed each of them from the respective bottles. The rat that dies ate from the bottle that had the poison pill in it. You didn't say that the digital scale had to be used to make the determination.

2007-01-10 21:52:00 · answer #4 · answered by Icanhelp 3 · 0 0

eat them.....if you die you got the poisonous one

2007-01-10 21:48:10 · answer #5 · answered by Bansch 3 · 0 0

weight them individually and that's it!

2007-01-10 21:55:30 · answer #6 · answered by astridmarie_y2k 2 · 0 0

Don't know.

2007-01-10 21:44:31 · answer #7 · answered by robert m 7 · 0 0

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