Multiply both sides by 2t:
5 -2t^2 = 3t + 3
-2t^2 - 3t +2 = 0
2t^2 + 3t - 2 = 0
(2t - 1)(t + 2) = 0
t = 1/2 t = -2
Bozo
2007-01-10 13:27:40
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answer #1
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answered by bozo 4
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5/2t-t=3+3/2t
3/2=3+3/2t (subtract t from 5/2t)
0=3
0 is not equal to 3, so there is no solution.
2007-01-10 21:26:15
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answer #2
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answered by 7
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I assume that you mean 5/(2t)-t=3+3/(2t) ?in this way :
multipy the equation by 2t so you have :
5-2t^t=3t+3
So 2t^2+3t-2=0
and then t=0.5 and -2
but if you mean (5/2)t-t=3+(3/2)t it is much easier :
=>(5/2-1)t=3+3/2t
=>(5/2-1-3/2)t=3
=>0t=3 in this way the equation dosn't have any answer!
2007-01-10 21:33:49
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answer #3
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answered by Arash J 2
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5/2t-t=3+3/2t
multiply each side by 2 to remove the fractions gives:
5t-2t=6+3t
Simplify gives:
3t = 6 + 3t
Subtract 3t from each side:
0 = 6
Since zero does not equal 6 there is no solution.
2007-01-10 21:29:04
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answer #4
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answered by Edgard L 2
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multiply both sides by 2t and you'll get:
5-2t^2 = 6t+3
make it all equal to zero so
-2t^2 - 6t +2 = 0
do the quadratic equation and your answers should be around
-3.3028 and .3028
2007-01-10 21:33:32
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answer #5
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answered by Tom 1
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first you multiply both sides by '2t' to eliminate them. the equation should look like:
5-t=3+3 or 5-t=6
subtract 5 from both sides to have
-t=1
divide each side by negative one and you will get the answer of
t= -1 (negative one)
2007-01-10 21:29:21
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answer #6
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answered by Anonymous
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i believe it is undefined. when i tried to work it out by subtracting 3/2t from both sides to get t on one side only, i got t-t which is 0 and the other side was 3... 0=3? no, thats undefined.
2007-01-10 21:27:43
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answer #7
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answered by ashesanne 2
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5/2t - t = 3 + 3/2t
5/2t - 3/2t -t = 3
(2/2t -t = 3 )*2t
2 - 2t^2 = 6t ----->> 2t^2 +6t -2 =0 and factorise.
2007-01-10 21:31:16
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answer #8
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answered by Diora 3
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5/2t-t = 3/2t
bring the other one over...
3/2t-3/2t=3
0=3
and sumthing mustave gone wrong or im just plain dumb
2007-01-10 21:30:00
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answer #9
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answered by Turtle~ 3
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