Tricky Math Question?

Question

Find three positive consecutive even integers such that the product of the first and second is 8 more than 38 times the third.

Answer 1

40, 42, 44

Answer 2

to find the three positive consecutive even integers you begin by.
1.writing out the three even integers.
2.write a correct equation to solve the word problem.
3.find the three integers.
4.pick the positive answers.
let the three consecutive even integers be: x, x+2, x+4.
the equation is this.
x(x+2)=8+38(x+4)
x^2 + 2x= 8 +152+38x
x^2+2x-38x-160=0
x^2-36x-160=0
x^2-40x+4x-160=0
x(x-40)+4(x-40)=0
(x+4) (x-40)=0
x= -4 or x= 40
first integer is x=-4 or x=40
second integers = -4+2=-2 or 40+2=42
third integers= -4+4=0 or 40+4=44
to find the three positive consecutive Even integers you pick 40, 42 ,and 44.
i hope it's no longer tricky, good luck.

Answer 3

what?