WRite the equation of a line passing theu 2,-3 and parallel to the line thru 4,1 and -2,-2?

Question

how do u do this can u please explain the steps

Answer 1

A: y = (1/2)x + -4

Find slope of line passing thru 4,1 and -2,-2

slope = m = (1+2)/(4+2) = 3/6 = 1/2
since these lines are parrallel then we can use this as the slope for the line we r finding

in slope intercept form
y = mx + b
since m = 1/2
y = (1/2)x + b

use the point 2,-3 to find b
-3 = (1/2) * 2 + b
-3 = 1 + b
-4 = b

so ur final answer is y = (1/2)x + -4

Answer 2

The line through (4,1) and (-2,-2) has a slope of 3/6 = 1/2 =.5.
So the line through (2,3) must also have a slope of .5.
So it's equation is y = .5 x +b
So -3=.5(2) =b
b= -3-1=-4
Therefore the required equation is y= .5x -4

Answer 3

slope = x1-x2/y1-y2
4-(-2)/1- (-2) = 6/3 = 2
therefore the slope of the line is 2

set the known point (2,-3) into y = ax+c
-3 = 2(2) + c
-3 - 4 = c
-7 = c

therefore the equation of the line is y=2x - 7

Answer 4

first, find the slope of equation of line through (4,1) and (-2,-2)
slope=rise/run=3 / 6=0.5
since the equation you're looking for is parallel to this line, then the slope is the same.
so y=0.5x+b
-3=1+b
b=-4
so the equation is y=0.5x-4

Answer 5

4,1 -2,-2 line: y= 1/2 x - 1
Parallel line: y = -2 x + 1

1: Find slope Y2-Y1/X2-X1
2: Substitue
3: NEgative recripol
4: Substitute for second line

oh... parallel... my bad... i have perpendicular... oh well... look at everyone elses. not mines. plz dont thumbs down mines... too lazy to change...

Answer 6

Slope formula:
m=(y2-y1)/(x2-x1)
m=(-2-1)/(-2-4)
m=1/2

Point-slope formula:
(y-y1)=m(x-x1)
y-(-3)=1/2(x-2)
y+3=1/2x-1
y=1/2x-4