crickets chirp about 30 times per minute when the temperature is 48 degrees, but 110 times when the temperature is 80 degrees.
write an equation for this relationship.
help with it, please?
2007-01-10 12:15:17 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
This requires an assumption that the relationship is linear. Treat this like ordered pairs, (48, 30) and (80, 110). The slope is equal to rise over run, or (110 - 30) / (80 - 48) = 80/32 = 2.5. Now you can express this is point-slope form. C - 30 = 2.5(T - 48), where T is the temperature and C is the number of chirps. If you'd rather have it in slope-intercept form, it becomes C = 2.5T - 120 + 30 = 2.5T - 90. You can quickly check it: 2.5(48) - 90 = 30 and 2.5(80) - 90 = 110.
If this were a real science problem instead of an algebra problem, it would be important to find out what temperature scale this is. It's almost definitely Fahrenheit, because 80 degrees Celcius is much hotter than it gets on the Earth's surface.
2007-01-10 12:21:50 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
assuming it's a linear relationship, then you can just use the formula y - y1 = (y2 - y1)/(x2 - x1) * (x - x1)
so your x's are temps and y's are chirps
so you have (48, 30) and (80, 110)
so y - 30 = (110 - 30)/(80 - 48) * (x - 48)
so y - 30 = 80/32 * (x - 48)
and y = 5/2 * x - 120 + 30
y = (5/2)*x - 90
2007-01-10 20:25:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Note that with this equation, at 36 degrees they don't chirp at all, and at temperatures less than 36 degrees, they have negative chirps.
2007-01-10 20:35:10 · answer #3 · answered by Steve A 7 · 0⤊ 0⤋