an isoscelese triangle has a base of 8cm n a perimeter of 44cm. wat are the legths of its legs?

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an isoscelese triangle has a base of 8cm n a perimeter of 44cm. wat are the legths of its legs?

2007-01-10 10:20:42 · 4 answers · asked by booger 2 in Science & Mathematics ➔ Mathematics

4 answers

(44-8)/2=18

2007-01-10 10:38:41 · answer #1 · answered by coop 2 · 0⤊ 0⤋

Let x = length of one leg.
Then perimeter = x + x + 8 = 2X + 8
2x + 8 = 44
2x = 36
x = 18 = length of eac of the two equal sides.
Check: 8 + 18 + 18 = 44
44=44

2007-01-10 18:41:58 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋

Since two legs of an isosceles triangle are equal, you can set this up to be..

P = 2x - 8
44 = 2x - 8
2x = 52
x = 26.

Therefore the lengths of the legs are 26 cm, 26 cm, and 8 cm.

2007-01-10 18:39:25 · answer #3 · answered by smawtadanyew 2 · 0⤊ 0⤋

p=44=8+2l
2l=36
l=18 cm
each leg is 18cm

2007-01-10 18:39:38 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋