2007-01-10 09:01:50 · 6 answers · asked by bluebird_chica 2 in Science & Mathematics ➔ Mathematics
please work it out
2007-01-10 09:07:28 · update #1
Note that the first term is a perfect square. It si equal to (2b)^2.
Note that the last term is a perfect square. It is 11^2.
This should immediately suggest to you that the factors are:
(2b +11)(2b+11)
If you check you can see that the middle term is11*2b +11*2b = 44b, so this is the correct factoring.
2007-01-10 09:28:50 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
Use x = -b +/- sq rt(b^2 - 4AC)/2a
where'a' is the coefficient of x^2
'b' is the coefficient of 'x'
'c' is the numerical coeffiecnt/
So
x = -44 +/- sq rt(44^2 - 4(4)(121))/2(4)
x = -44 +/- sq rt(1936 -1936)/8
x = -44 +/- sq rt(0)/ 8
x = -44/8 = -11/2 = -5.5
As discrimant : (b^2 - 4AC = 0) there is only one real root at -5.5.
2007-01-10 17:15:38 · answer #2 · answered by lenpol7 7 · 0⤊ 0⤋
(2b + 11) (2b + 11)
or
(2b + 11)^2
2007-01-10 17:08:20 · answer #3 · answered by Doug R 5 · 1⤊ 0⤋
(2b+ 11) (2b+ 11)
or (2b + 11)^2
2007-01-10 17:07:11 · answer #4 · answered by chris 2 · 1⤊ 0⤋
(2b+11)²
2007-01-10 17:04:34 · answer #5 · answered by bequalming 5 · 1⤊ 0⤋
(2b+11)(2b+11)or
(2b+11)^2
2007-01-10 17:14:27 · answer #6 · answered by Anonymous · 0⤊ 0⤋