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14 answers

194

2007-01-10 08:55:13 · answer #1 · answered by Anonymous · 1 0

Let the 3 digit number be a b c
b = c + 5; a = b - 8
Now a + 8 = b so a = 1 which leads to b = 9 which ,in turn , leads to c = 4
The 3 digit number is thus 1 9 4

2007-01-10 09:55:54 · answer #2 · answered by Como 7 · 0 0

First assign each digit a variable; your three digit number will be XYZ, where X represents the hundreds digit, Y represents the tens digit, and Z represents the ones digit.

From the problem, we are given the following two equations:
Z+5=Y
X+8=Y

Remember that all digits must be positive, and must represent a number between 1 and 9. If you look at the second equation, X+8=Y, you realize that the only way for Y to fulfill this requirement is if X=1. Thus, X=1 and Y=9. You then plug Y=9 into the first equation, and find that Z=4.

Thus,
X=1
Y=9
Z=4

2007-01-10 08:58:57 · answer #3 · answered by James E 2 · 0 0

Let be the three digit number in decimal expansion.

Given:

b = c + 5
b = a + 8
a: nonzero

Since b = a + 8, and a is nonzero, a must equal 1 and b must equal 9. Then c must equal 4.

Thus = 194.

2007-01-10 08:59:46 · answer #4 · answered by NietzcheanCowboy 3 · 0 0

194

2007-01-14 00:04:30 · answer #5 · answered by Anonymous · 0 0

194

2007-01-10 08:59:27 · answer #6 · answered by sandra s 2 · 0 0

194

2007-01-10 08:57:15 · answer #7 · answered by green day luver 2272 2 · 0 0

194

2007-01-10 08:57:09 · answer #8 · answered by cutest pooky 3 · 0 0

194

2007-01-10 08:56:13 · answer #9 · answered by premed student 2 · 0 0

194

2007-01-10 08:55:30 · answer #10 · answered by g8bvl 5 · 0 0

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