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a charge of -5 x 10^-7 C is 10cm from a charge of +6 x 10^-6 C.
find the magnidue and directin of the force on each charge.

is there a formula or something? i have to do more problems like this and i just really need to know how to do it. thanks.

2007-01-10 08:36:08 · 2 answers · asked by becky 2 in Science & Mathematics Physics

the equation my teacher told us to use today is F=(Kq1q2)\(d^2)
is that the same, basically?

2007-01-11 09:22:06 · update #1

2 answers

F = 1/(4*pi*e0) * q1 * q2/r^2

Where e0 is the constant epsilon 0, pi is obvioulsy the constant pi, q1 is a charge, q2 is the other charge, and r is the distance between them. This will give you magnitude.

How to do opposite charges act? Do the attract or repel? This should tell you direction.

2007-01-10 08:40:10 · answer #1 · answered by msi_cord 7 · 1 0

well there is coulombs law

F= q1*q2/(4*pi*E*r^2) *(rq1q2)
here f is the force betn two charges q1 n q2,
div by pi =3.14, E = Eo Er
where Eo the permitivity in free space =1
n Er is the pemitivity iin the medium(see ur question)
n r is the distance betn the charges the term (rq1q2) gives the direction of the field

2007-01-10 22:27:13 · answer #2 · answered by curious 1 · 0 0

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