Please I need the answer to this problem ASAP!!!!?

Question

Find the 2 smallest consecutive odd integers whose sum is atleast 49. Write an equation and solve.

Answer 1

Let x be one of the odd integers.
Then x + 2 would be the next odd integer, since odd numbers differ by 2.

It follows that the first integer, x, added to the second integer, x + 2, would be at least 49. That is

x + x + 2 >= 49

Solving this inequality,

2x + 2 >= 49
2x >= 47, therefore
x >= 23.5

Now, since x is an odd integer, what is the smallest odd value of x greater than 23.5? The answer to that is not 24 (since it's even), but it's 25.

This means the two smallest consecutive odd integers whose sum is at least 49 are 25 and 27. They add up to 52, but that's the best you can do given the circumstances.

Answer 2

Let the first odd integer be 2n+1 where n is an positive
then the second odd integer is 2n+3
Now (2n+1) + (2n+3) >= 49
4n+4 >= 49
4n>=45
n>=45/4=11.25 or n >=12 as n must be an integer and this must be true for the equation to work; rounded up to next greatest integer
So take n=11 so the first is 2(12)+1 = 25; then the
second is 2n+3 = 2(12)+3 = 27

Answer 3

25 and 27 b/c 23+25=48

Answer 4

x+(x+2) >= 49
2x+2>=49
2x>=47
x>=23.5
x must be 25 and the next odd integer is 27

Answer 5

consecutive odd integers will be x and x+2

Set these equal to 49

Solve for x

Rewrite so that x > or equal to the answer

Answer 6

25 and 27 but idk about an equation