2007-01-10 08:14:34 · 7 answers · asked by krystal r 1 in Science & Mathematics ➔ Mathematics
No.
They are not a pythagorean triple:
2^2 + 3^2 = 13, which does not equal 6^2, or 36.
Also, 2+3 < 6, so they are not a triangle, period.
2007-01-10 08:18:24 · answer #1 · answered by Jerry P 6 · 0⤊ 0⤋
In general, to find if a, b and c could be the sides of a right triangle, where c > a, b (i.e. c is the largest length), see if a^2 + b^2 = c^2, where ^2 means squared. To see if they could be a triangle AT ALL, see if c < a+b; if this fails, then no such triangle with these sides exists.
2007-01-10 08:47:46 · answer #2 · answered by Anonymous · 1⤊ 0⤋
No. The pythagorean theorem states that for a right triangle, the hypotenueuse squared must equal the sum of the squared sides. Basically, a and b are your sides, c is your hypot.
a^2 + b^2 = c^2
2007-01-10 08:19:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
If the lenght of two of the three facets have been any of the three numders you are able to make best triangles. you have gotten a best triangle with a base of 12 and altitude of 8 however the 0.33 side may be approximately 14.5 or so. that's a results of a regulation reguarding best attitude triangles which any grade scholar could desire to comprehend.
2016-11-28 02:35:02 · answer #4 · answered by carmean 4 · 0⤊ 0⤋
no because 2^2 + 3^2 is not equal to 6^2
4 + 9 = 36
13 = 36
see?
2007-01-10 08:21:17 · answer #5 · answered by Ray 5 · 0⤊ 0⤋
no
in any triangle a+b>c for and side lengths a, b, and c
set:
a=2
b=3
c=6
a+b=2+3
so it cannot even be a triangle
2007-01-10 08:19:12 · answer #6 · answered by Bob H 1 · 1⤊ 0⤋
why don't you work out the math problem, justify your answer and then tell all of us the answer? Nice try, but stop trying to get people to do your homework
2007-01-10 08:23:17 · answer #7 · answered by karma 7 · 1⤊ 0⤋