Imagine a square with number 8 in the middle. In each corner (starting at the top left and going clockwise) there are numbers 4,6,2 then 8. Another square - 30 in the middle and the 4 numbers are 9,2,7 then 3. How do I reach the middle number using the 4 outer numbers. Using the same process for both.
2007-01-10 07:28:51 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The numbers can be used in any order. But you have to use the same process for both squares to reach the middle number.
You can add, takeaway, multiply, whatever. As long as you use the 4 outer numbers to reach the middle.
2007-01-10 09:07:12 · update #1
Are you sure you have the numbers around the second one correct? And you have started in the top left and gone clockwise for both examples?
2007-01-10 07:42:00 · answer #1 · answered by Funky Little Spacegirl 6 · 0⤊ 0⤋
18
2007-01-10 07:31:49 · answer #2 · answered by pepzi_bandit 2 6 · 0⤊ 1⤋
hmm tough one. are their rules as to which functions you can use (are they just + or - to get to the answer?) and does your equation have to go in that order (for example do you have to use 4 then the 6 then the 2 then the 8?)
I can't figure it out, but if you get it, post it, I'm curious now! good luck
2007-01-10 07:45:07 · answer #3 · answered by strtat2 5 · 0⤊ 0⤋
4 +2 - 6 + 8 = 8
Is that what you mean?
2007-01-10 07:35:00 · answer #4 · answered by scruffy 5 · 0⤊ 2⤋
i dunno, by one train of thought, the first answer should be 10, not 8, and by another train of thought, the second answer should be 9 or maybe 28. or, it could be all numbers added together and divided by 2, which i'm not good enough at doing math in my head to tell you off-hand.
2007-01-10 07:37:28 · answer #5 · answered by Dayne's gal 2 · 0⤊ 1⤋