A triangle has the measurements of:
Angle A = 71˚. Side a = 29.5 mm, and side c = 30 mm.
Calculate the length of side b.
2007-01-10 07:27:00 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
30 mm is between Angles A and B.
29.5 mm is between Angles B and C.
Angle A (71 degrees), side c (30 mm) and Angle B are at the bottom, or the base of the triangle.
Side b is the hypotenuse.
Side a (29.5 mm) is thhe adjacent side.
2007-01-10 07:40:21 · update #1
use sin rule:
sin A/ a = sin C / c
sin 71/ 29.5 = sin C /30
C= anti sin ( sin71/29.5) x 30
B= 180 - 71 - C
hope it helps
2007-01-10 07:56:36 · answer #1 · answered by Leicester B 2 · 0⤊ 0⤋
a/sinA = c/sinC
29.5/sin71=30/sinC
sinC = (30*sin 71)/29.5 = 0.9615443142
C = arcsin(0.9615443142) = 74.0588 degrees
Therefore angle B = 180 -71-74.0588= 34.9412 degrees
b/sinB = a/sinA
b = a*sinB/sinA
b= 29.5*sin34.9412/sin71
b = 17.8692 mm
2007-01-10 08:21:07 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
What does the triangle look like? Which two sides is angle A between?
2007-01-10 07:32:31 · answer #3 · answered by Brad 4 · 0⤊ 0⤋