quadratic
2007-01-10 06:28:44 · 11 answers · asked by Dre 1 in Science & Mathematics ➔ Mathematics
x^2 - 10 + 10 = 0 + 10
x^2 = 10
sq root (x^2) = sq root (10)
x = +/- sq root (10)
2007-01-10 06:34:15 · answer #1 · answered by Leicester B 2 · 0⤊ 0⤋
x² - 10 = 0
Add 10 to both sides:
x² = 10
Take square root of both sides, remembering that the square root can be either positive or negative:
x = 屉10
Alternate method:
x² - 10 = 0
Factor as a difference of squares:
(x + â10)(x - â10) = 0
Set each factor equal to zero:
x + â10 = 0
x = -â10
x - â10 = 0
x = â10
2007-01-10 14:31:58 · answer #2 · answered by Jim Burnell 6 · 1⤊ 0⤋
The quadratic equation still applies, but b = 0.
(-b +/- sqrt(b² - 4ac)) / (2a)
(-0 +/- sqrt(0² - 4(1)(-10)) / (2(1))
+/- sqrt(-40) / 2
+/- 2 * sqrt(10) / 2
+/- sqrt(10)
2007-01-10 14:35:20 · answer #3 · answered by Dave 6 · 0⤊ 0⤋
x=2 times the square root of 5
2007-01-10 14:37:46 · answer #4 · answered by Da~thic~bac blak 1 1 · 0⤊ 1⤋
x^2-10=0
(x + rt10)(x - rt10) = 0
x = rt10
x = -rt10
2007-01-10 14:35:06 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(x+â10)(x-â10)=0
x = â10 or x = - â10
2007-01-10 14:32:15 · answer #6 · answered by bequalming 5 · 1⤊ 0⤋
Are you trying to solve for X?
x^2=10
x=+ or - 3.16
Hope that answered your question.
2007-01-10 14:33:37 · answer #7 · answered by TJ 2 · 0⤊ 0⤋
x^2-10=0
(x-5)(x+5)=0
x=5, -5
2007-01-10 14:34:17 · answer #8 · answered by chrisjptine 1 · 0⤊ 2⤋
x1=+sqrt(10)
x2= - sqrt(10)
2007-01-10 14:34:02 · answer #9 · answered by Anonymous · 0⤊ 0⤋
positive or negative 3.16227766
2007-01-14 14:28:28 · answer #10 · answered by huronda_hottie_2006 1 · 0⤊ 0⤋