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The legs of a right triangle are 3 and 8 cm long, respectively. What is the length of the hypotenuse? If necessary, round your answer to two decimal places.

2007-01-10 06:22:20 · 9 answers · asked by Rattiesrule 2 in Science & Mathematics Mathematics

A 45- 45- 90 triangle has a hypotenuse of length 12. What is the length of one of the legs? If necessary, round your answer to two decimal places.

2007-01-10 06:43:46 · update #1

9 answers

hypotenuse
=sqrt[3^2+8^2]
=sqrt 73
=8.544 cm

2007-01-10 06:28:15 · answer #1 · answered by openpsychy 6 · 0 0

Pythagorean Theorem: a^2 + b^2 = c^2

3^2 + 8^2 = c^2

9 + 64 = c^2

c = sqrt(73) cm

2007-01-10 06:28:18 · answer #2 · answered by MamaMia © 7 · 1 0

hypotenuse= sqrt(3*3+8*8)= sqrt(9+64)= sqrt(73)= 8.544003

2007-01-10 06:35:54 · answer #3 · answered by teo 1 · 0 0

using Pithagoras
c^2= a^2+b^2
c^2= 3^2+8^2
c^2=9+64=73
c= square root(73)= 8.54

2007-01-10 06:30:18 · answer #4 · answered by ENA 2 · 1 0

The answer is 8.54 for the Hypotenuse.

2007-01-10 06:30:49 · answer #5 · answered by TJ 2 · 0 0

...

square root of (3^2 + 8^2)
= sqr73
=8.544
...

2007-01-10 06:32:16 · answer #6 · answered by Jon 3 · 0 0

sqrt(9+64)

2007-01-10 06:27:34 · answer #7 · answered by gjmb1960 7 · 0 0

What are the answers so I can check my work.... Also, people can't answer questions that reference diagrams if you don't provide the diagrams.

2016-05-23 05:18:41 · answer #8 · answered by Anonymous · 0 0

8.544

2007-01-10 06:27:42 · answer #9 · answered by electro_nnn 2 · 0 0

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