I would like to see how they got the ans. for 28m^4-14m^3+7m^2?

Answer 1

28m^4 - 14m^3 + 7m^2 = 0

7m^2(4m^2 - 2m + 1) = 0

7m^2 ( 2m - 1)(2m - 1) = 0

- - - - - - - - - -

Roots

7m^2 = 0

7m^2 / 7 = 0/7

m^2 = 0/7

m^2 = 0

m^2 = √0

m = 0

- - - -

Roots

2m - 1 = 0

2m - 1 + 1 = 0 + 1

2m = 1

2m/2 = 1/2

m = 1/2

m = 0.5

- - - - - - - -

Check for m = 0

28 m^4 - 14m^3 + 7m^2 = 0

28(0)^4 - 14(0)^3 + 7(0)^2 = 0

28(0) - 14(0) + 7(0) = 0

0 - 0 + 0 = 0

0 = 0

- - - - - - - - -

Checking for m = 0.5

28m^4 - 14m^3 + 7m^2 = 0

28(0.5)^4 - 14().5)^3 + 7(0.5)^2 = 0

28(0.0625) - 14(0.125) + 7(.25)

1.75 - 3.5 + 1.75 = 0

- 1.75 + 1.75 = 0

0 = 0

- - - - - - -

m = 0

and

m = 0.5

are both solutions


- - - - - -s-

Answer 2

what is the question find the roots? of
28m^4-14m^3+7m^2=0
It has 4 roots 2 of them are 0
So find the roots for 28m^2-14m+7=0
And you are all set

Answer 3

All monomials in this trinomial have a factor of 7m². Factor by that:

7m²(4m²2 - 2m + 1)

The second factor there does not have integral roots, so I'm leaving it like that. You can use the quadratic formula on it if you so choose.