Chemistry calculations?

Question

Ascorbic acid, (vitamin C, C6H8O6) is a water soluble vitamin. A solution containing 80.5 g of ascorbic acid dissolved in 210 g of water has a density of 1.22 g/mL at 55 degrees C. Calculate the following:

the mass percentage

the mole fraction

the molarity

the molarity of ascorbic acid in this solution

Answer 1

1) Mass percentage of solution is computed as follows:

% (w/w) = [80.5 g / (80.5 + 210 g)] x 100 = 27.71%

2) Molarity is computed knowing the moles of ascorbic acid (AA) in solution.
Molar mass AA = 176 g/mol
moles of AA = 80.5 g / 176 g/mol = 0.4573 moles

Assume that density of water is equal to 1 g/mL, it means that we have 210 g = 210 mL = 0.210 L

Molarity = 0.4573 / 0.210 L = 2.17 M

3) Molar fraction is computed knowing moles of AA and moles of water.

moles of H2O = 210 g / 18 g/mol = 11.66 moles
we already know moles of AA = 0.4573 moles

molar fraction AA = 0.4573 / (0.4573 + 11.66) = 0.0377

4) The molarity of Ascorbic acid in this solution is as calculated in (2) equal to 2.17 M

Good luck!

Answer 2

Dude, I'm not going to do your entire homework assignment. Get a chemistry book (perhaps the one your professor or HS teacher assigned to you).

Answer 3

what you basically need to do is answer each question one by one...if your in need of help...there are tutor sessions, and your professor will help you...