if f(x) = 7x^2 + 3 and g(x)=2x-9 then g(f(2))=53 How do you get this?

Answer 1

f(x) = 7x^2+3
g(x) = 2x-9
g(f(x)) = 2(7x^2+3) - 9
g(f(x)) = 14x^2 -3
g(f(2)) = 14(2)^2 -3
g(f(2)) = 56-3 = 53

Answer 2

Strict substitution.

f(2) means to take f(x) and put in a 2 everywhere that the formula has an x. Thus:
f(2) = 7(2)^2 + 3 = 7(4)+3 = 28 + 3 = 31

g(f(2)) means to take g(x) and put in the result of f(2) everywhere that the formula has an x. Thus:
g(f(2)) = 2(31) - 9 = 62 - 9 = 53

Answer 3

Remember in the order of operations, paretheses always come first.

First figure f(2) which equals 7*2² + 3 = 7*4 + 3 = 28 + 3 = 31

Now figure g(31) = 2*31 - 9 = 62 - 9 = 53. QED

Answer 4

First, f(2)=7*2^2+3= 31.
And g(31)=2*31-9=62-9=53.

Answer 5

first you calculate f(2) by replacing x with 2;if f(x)=7(x*x)+3 that means that f(2)=7(2*2)+3=7*4+3=31
then you replace x from g(x) with f(2).if g(x)=2x-9 you get g(f(2))=2*31-9=62-9=53.
Easy as that.

Answer 6

g(f(2)) means that replace the "x" in g(x) by the function f(2)

I'll show you
First solve f(2) = 7 * 2^2 + 3 = 31
g(f(2)) = 2 (31) - 9 = 53

Answer 7

You evaluate f(x) and then put the answer into g(x).

Solution:
f(x) = 7x^2 + 3
f(2) = 7(2^2) + 3
f(2) = 7(4) +3
f(2) = 28 + 3
f(2) = 31.

g(x) = 2x - 9
g(31) = 2(31) - 9
g(31) = 62 - 9
g(31) = 53.

Q.E.D

Answer 8

f(2)=7*4+3
f(2)=31
g(31)=2*31-9
=62-9
=53