the number.
2007-01-10 02:47:23 · 34 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
63
2007-01-10 03:17:09 · answer #1 · answered by mebbe_sew_mebbe_knot 1 · 5⤊ 0⤋
Let x = units digit let y = tens digit The original number is equal to 10y + x The reversal of the digits results in 10x + y (10y + x) - 27 = 10x + y x + y = 7 x = 7 - y 10y + (7 - y) - 27 = 10(7 - y) + y 9y - 20 = - 9y + 70 18y = 90 y = 5 x = 2 The original number is 52 The new (reversed digits) number is 25 Check QED
2016-05-23 04:03:11 · answer #2 · answered by Elizabeth 4 · 0⤊ 0⤋
The Number is 63
2007-01-10 02:53:28 · answer #3 · answered by big totti fan 1 · 0⤊ 0⤋
Let x and y be the 2 digits of the number.
(x be the tens place digit and y be the units place digit)
The number is : 10x + y
Given : Sum of 2 digits = 9
Hence, x + y = 9 .................. (1)
By The second condition of 27 being subtracted from the number,
10x + y -27 = 10y + x
9x-9y = 27
x - y = 3 .......................... (2)
Solve equations (1) and (2) Simultaneously
x + y = 9
x - y = 3
___________
2x = 12
x=6
y=3
The number is 10x + y ,
i.e 10*6 + 3 = 63
2007-01-10 16:10:56 · answer #4 · answered by aditya r 1 · 0⤊ 0⤋
n: number: ab
a + b = 9 then it must be a multiple of 9
that narrows it down to 09 18 27 36 45 54 63 72 81 90
we just have to find the two reversed numbers that their difference is 27, these numbers are 63 and 36
so the number you r looking for is 63
2007-01-10 03:22:39 · answer #5 · answered by Anonymous · 0⤊ 0⤋
The Answer is 63 or -36
Case 1: 63 - 27 = 36 !!!
Case 2: -36 - 27 = -63 !!!
NOTE: Here the minus sign ( - ) represents the value of the number 63 or 36 but does not represent " -6 "
2007-01-10 02:56:48 · answer #6 · answered by Prakkhar Gupta 1 · 1⤊ 0⤋
The number is 63
2007-01-11 12:51:21 · answer #7 · answered by cutest pooky 3 · 0⤊ 0⤋
The Number is 63
6 + 3 = 9
63 - 27 = 36
2007-01-10 03:03:39 · answer #8 · answered by GTA 2 · 0⤊ 0⤋
63 because 6+3=9. 63-27=36
2007-01-10 02:54:19 · answer #9 · answered by Anonymous · 0⤊ 0⤋
The number is 63.
Let the digits in unit place be y and that in the tens place be x.so the number is 10x+y.
sum of digits x+y=9
the number in the reversed form is 10y+x.
if 27 is subtracted frommthe original numner(10x+y) the digits are reversed so
(10x+y)-27=10y+x
simplifying we have 10x+y-27=10y+x.
9x-9y=27
x-y=3--------1
also x+y=9(sum of digits is 9)--------------2
solving 1& 2 simutaneoulsy we have x=6 and y=3.
so number is 10x+y=63
just to countercheck
63-27=36 which is the reversed number...
2007-01-11 03:49:14 · answer #10 · answered by srinsrinsri 2 · 0⤊ 0⤋
Let the number be 10x+y where x and y are single digit number.x+y=9 and 10x+y-27=10y+x are given that is x+y=9 and 9x-9y=27(that is x-y=3) are given whose solution is x=6,y=3.therefore the given two digit number is 10(6)+3=63.
2007-01-10 02:55:39 · answer #11 · answered by sannu 1 · 3⤊ 0⤋