Please help!
I'm doing an investigation into the behaviour of capacitors in audio electronics and have made some simple filter networks. I understand how the filters work and their frequency response and everything, but why do you get a slightly curvy square wave shape as the output signal? Why wouldn't it just be a normal square wave or even a sine wave? Please help if you can! Thanks!
2007-01-10 02:16:26 · 3 answers · asked by wonder.crumpet 2 in Science & Mathematics ➔ Other - Science
A square wave contains lots of different frequencies, and your filter only cuts off some of them.
The square wave is made from the sum of a set of sine waves - if the frequency of the square wave is "f", then it's made from the sum of sine waves at "f", "3f", "5f" etc. (at different amplitudes).
The more of these sine-waves that get past your filter, the more "square" your output wave - and the fewer you get the more "sinusoidal" it is. So, to get a pure sine wave you need your filter to have a cut-off just above "f" (i.e. nothing gets through at 3f or above), so that all the other sine waves are removed.
2007-01-10 21:08:35 · answer #1 · answered by Gavin P 2 · 0⤊ 0⤋
Need more info in the signal in and the signal out. A square wave is one of the best test for broad band pass.
2007-01-10 07:37:51 · answer #2 · answered by JOHNNIE B 7 · 0⤊ 0⤋
Any answer I supply alongside those lines will unavoidably be intuitive via fact it`s been too long considering that i become uncovered to the mathematics required to examine an impulse function. i'm in over my head yet right that's how i inspect it. each guy or woman frequency interior the frequency area is a sine wave. How else are you able to strategies-set a voltage upward thrust time of 0 without which incorporates each guy or woman sine wave frequency interior the spectrum.
2016-12-12 08:22:12 · answer #3 · answered by girardot 4 · 0⤊ 0⤋