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The legs of a right triangle are 5 and 7 cm long, respectively. What is the length of the hypotenuse? If necessary, round your answer to two decimal places.

2007-01-10 01:42:22 · 18 answers · asked by Rattiesrule 2 in Science & Mathematics Mathematics

18 answers

To do this, use the formula: a^2+b^2=c^2
25+49=c^2
74=c^2
8.60=c

2007-01-10 01:46:31 · answer #1 · answered by Snoopy 5 · 2 0

a² + b² = c²

5² + 7² = c²

25 + 49 = c²

74 = c²

8.60 = c

2007-01-10 01:54:31 · answer #2 · answered by Anonymous · 1 0

Use the Pythagorean Theorem: a^2+b^2=c^2
5^2+7^2=c^2
25+49=c^2
74=c^2
8.6023252670...=c
8.60=c

2007-01-10 15:50:22 · answer #3 · answered by cutest pooky 3 · 0 0

This is so easy-peesy.According to pythagoras theory,the length
of the square of the hypotenuse is equal to the squares of both the base and the altitude.Therefore I conclude that the length of
this given right triangle is approximately 8.60 cm.The actual
length of the hypotenuse is too long to type on this page

2007-01-10 04:18:51 · answer #4 · answered by Christine$hotbabe 3 · 0 0

The length is the square root of the sum of the squares of the legs. So 25+49= 74. The square root is 8.60

2007-01-10 01:46:57 · answer #5 · answered by Anonymous · 2 0

Use Square root of 7 square plus 5 square= 8.60 cm

2007-01-10 01:53:59 · answer #6 · answered by MG 2 · 1 0

Remember Pythagoras' theorem: c^2 = a^2 + b^2
Hence square root of 25 + 49 = your hypotenuse = 8.60

2007-01-10 01:48:30 · answer #7 · answered by Anonymous · 2 0

Pythagorean Theorem: a^2 + b^2 = c^2 3^2 + 8^2 = c^2 9 + 64 = c^2 c = sqrt(73) cm

2016-05-23 03:48:08 · answer #8 · answered by Anonymous · 0 0

hypotenuse^2 = 5^2 + 7^2 = 74
hypotenuse = sqrt(74) = 8.6

2007-01-10 01:47:52 · answer #9 · answered by James Chan 4 · 2 0

Pythagorean Theorem

c² = a² + b²

c² = √(5)² + (7)²

c² = √25 + 49

c³ = √74

c = 8.602325267 cm

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2007-01-10 02:30:35 · answer #10 · answered by SAMUEL D 7 · 0 0

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