What would be the limiting factor of the acid in a experiment between magnesium and sulphuric acid?

Question

And how could I word this in my essay?

Answer 1

The acid will react with the metal producing hydrogen gas and a salt. For a soluble salt this would carry on until either all of the magnesium or acid had reacted - it would depend on their relative amounts as to which one went first.
However, this does NOT apply for Mg and H2SO4 because the salt that results from the reaction (MgSO4) is rather insoluble. What will happen is that the reaction will start, as normal, but then stop as a layer of insoluble magnesium sulphate builds up on the metal protecting it from further attack.
So maybe the limiting factor is the surface area of the magnesium?

Answer 2

Magnesium ribbon is a organic sturdy form if the metallic, subsequently while its powder, it potential that it quite is been oxidised - burned to the oxide- magnesium oxide. hence in case you place magnesium oxide (powder) into the sulphuric acid the reaction would be better via fact magnesium oxide is composed of O. MgO will dissolve in sulphuric acid.

Answer 3

My answer is that that the magnesium would desolve.....

My missus however.....
2Mg + 2SO3H = 2SO3 - 2H+ +2Mg+ +2e-
2Mg 03S +H2 (i think)
limiting factor...... Oxidising power of Mg pH of SO3H- ie is it diluted?

this means absolutly nothing to me, i might of even wrote it wrong. i hope it helps you though.