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1 answers

dr - bcosx dr = b r sinx dx

dr (1 - bcosx) = b r sinx dx

dr/r = b sinx dx / (1 - bcosx)

Edit:

OOPS Forgot the b on the sin x dx part

2007-01-10 00:37:16 · answer #1 · answered by z_o_r_r_o 6 · 0 0

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