2007-01-09 23:39:48 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I'm not 100% certain what you're talking about, so all I can do is guess.
You want dy/dx when y = sqrt(x).
To solve for this, note that sqrt(x) = x^(1/2). All you have to do is then use the power rule.
y = x^(1/2)
dy/dx = (1/2)x^(-1/2)
But we get rid of negative exponents by putting them as a fraction (1 over its positive power). Therefore, we have
dy/dx = (1/2) * (1/[x^(1/2)])
dy/dx = 1/[2sqrt(x)]
2007-01-09 23:49:06 · answer #1 · answered by Puggy 7 · 0⤊ 1⤋
do u want integration or differentiation of this
integration---- (x)to the pow3/2 divided by 2/3 plus C
differentiation-- 1/{2*(sqrt of x)}
2007-01-09 23:53:12 · answer #2 · answered by Cool 1 · 0⤊ 0⤋
do you mean (sqrt x)(dy/dx)? Well, what do you want?
2007-01-09 23:48:44 · answer #3 · answered by AAK 2 · 0⤊ 0⤋
You'll have to write your question in terms we understand!
2007-01-10 01:15:30 · answer #4 · answered by Gnomon 6 · 0⤊ 0⤋
dx/xdy
2007-01-10 00:04:03 · answer #5 · answered by Anonymous · 0⤊ 0⤋
1/2x^(-1/2)
2007-01-09 23:50:53 · answer #6 · answered by Brad J 2 · 0⤊ 0⤋