English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories
0

Cathy has a collection of dimes and quarters. The number of dimes equals the number of quarters. She has a total of $2.80. How many of each coin does Cathy have?
[Hints: Let n = number of dimes. Since each dime has a value of 10 cents, the value of n dimes is 10n. Since the number of quarters is also n, the value of n quarters is 25n. Also change the value of $2.80 into cents.]

2007-01-09 17:19:21 · 4 answers · asked by Jennifer 1 in Science & Mathematics Mathematics

4 answers

Well, let's use the hint you have. Change $2.80 into cents. That makes 280 cents. She has n dimes so the total value of money in dimes that she has is 10n cents. She has n quarters, so the total value of quarters she has is 25n cents. Write out an equation to represent the total amount of money she has:
10n + 25n = 280.
Add the left side:
35n = 280
Divide both sides by 35:
35n/35 = 280/35
n = 8.

=> This means that she has 8 dimes and 8 quarters.

(Double check by figuring out how much money 8 dimes and 8 quarters make and it should be $2.80.)

2007-01-09 17:26:25 · answer #1 · answered by Wendy C 2 · 0 0

Why did you send the problem to Yahoo answers when you know to solve the problem?

2007-01-10 01:53:28 · answer #2 · answered by alpha 7 · 0 0

you have solve the problem by giving the hint
next time leave it for us to figure out.
cheers.

2007-01-10 10:12:32 · answer #3 · answered by bright 247 2 · 0 0

.1n+.25n=2.8
.35n=2.8
8 of each

2007-01-10 01:28:29 · answer #4 · answered by TiGeR 4 · 0 0

fedest.com, questions and answers