a 45.0 kg stands on a 150 kg plank where the plank is originally at rest on a ice surface.
the ice surface is frictionless.
the girl walks constantly 1.5 m/s relative to the plank
2007-01-09 16:41:09 · 6 answers · asked by Tuan-Minh N 1 in Science & Mathematics ➔ Physics
V(girl) - V(plank) = 1.5
We started at rest, and momentum is conserved,
so V(girl)*M(girl) +V(plank)*M(plank) = 0
2007-01-09 17:05:21 · answer #1 · answered by virtualguy92107 7 · 1⤊ 0⤋
The velocity of the girl relative to the ice is 0. the velocity of the plank relative to the ice is 1.5 m/s.
This is bcause there is no friction between the plank and the ice, so the girl is walking on a plank that is sliding.
2007-01-10 05:17:04 · answer #2 · answered by civilman 2 · 0⤊ 0⤋
holy crap, I was reading that question in tutorial, its something like .1 and .3
Use momentum, and newton's third law
2007-01-09 16:47:07 · answer #3 · answered by adklsjfklsdj 6 · 0⤊ 0⤋
no friction, no movement, as its impossible to get started. also acceleration is zero.
2007-01-09 16:50:45 · answer #4 · answered by i must be bored, im on Y answers 3 · 0⤊ 0⤋
shes high velocity
2007-01-09 17:08:29 · answer #5 · answered by Anonymous · 0⤊ 0⤋
if there is no friction you couldn't walk
2007-01-09 16:45:49 · answer #6 · answered by jake 5 · 0⤊ 0⤋