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if one point is (-7,8) and another is (7,3) how do i find a graph of a straight line that goes through both points?

2007-01-09 15:34:39 · 7 answers · asked by moestudios 1 in Education & Reference Homework Help

7 answers

What exactly do you mean find a graph?

http://nces.ed.gov/nceskids/createagraph/

You can try that one. Are you trying to find a premade one? Why can't you just draw it up?

Well I hope that website helps you

2007-01-09 15:40:32 · answer #1 · answered by Venezuela 2 · 0 0

You want the formula of the line that contains both points. The formula is going to look like this y = mx + b. The final answer will always have an x and a y in it, but you need to find m and b. The m is the slope of the line, the angle at which it lies; and b is the y-intercept, the point at which it crosses the y axis. Figure out m, figure out b. That's it!

The slope is found by finding the difference (that means subtraction) between the points:

slope = (the difference in y's) divided by (the difference in the x's).

The first y is 8 and the second is 3, so the difference is 5.

The first x is -7 and the second is 7, so the difference is -14.

5 divided by -14 is -5/14. This is m.

Now we have y = -5/14 x + b. To find b we plug in either of our points for x and y and we'll get the same b when we solve it, regardless of which point we plug in. Let's try the second point:

3 = -5/14 (7) + b so b = 11/2

Finally y = -5/14 x + 11/2 too many fractions, so lets multiply everything by 14:

14 y = -5 x + 77 and move the x to the other side to get it in standard form:

5 x + 14 y = 77

Note: 5/14 is 5 over 14; 11/2 is 11 over 2

2007-01-10 00:08:06 · answer #2 · answered by bigcha 2 · 0 0

1. get some graph paper.
2. Draw a line in the middle, going left-right, and label it "x"
3. draw another line from the middle, going up.down, and label it "y"
4. Label the point where the line cross (the origin) as "0"
5. Starting from 0, make a series of marks, all the same distance apart. On metric graph paper, go for one per centimetre. The ones to the RIGHT of 0 are labelled 1, 2, 3, ..... Make sure you have 7 or more. The ones to the LEFT are labelled -1, -2, -3... down to -7.
6. in the same way, mark the up/down line. Marks ABOVE 0 go 1,2,3.. to 8 or more. Marks BELOW the zero go -1,-2,-3...

7. Go LEFT to where x= -7, and UP to where y=8. Make a small mark.
8. Go RIGHT to where x=7, and UP to where y=3. Make another mark.

DRUMROLL...
9. With a RULER, line up the two marks and draw a line between them.
Congratulations- you have found a graph. It's on your desk.

2007-01-10 00:02:14 · answer #3 · answered by Alan 6 · 1 0

if you mean you want to find an equation, then you would first find the slope and work from there. so to find the slope, it is y2-y1/x2-x1.
so 3-8/7+7.
-5/14.
so now to find the equation.
in standard form, all equations are y=mx+b, m being the slope. now you find b. lets take the point (7,3)
3=-5/14(7)+b
so 3=-2.5+b
so b = 3+2.5. thus
b=5.5.
so now, your equation is
y= -5/14x+5.5
im pretty sure thats right. i did a check using both points and they were off by almost nothing (about .000001)
: )

2007-01-09 23:42:21 · answer #4 · answered by ♥♫☺bee yourself☺♫♥ 3 · 0 0

just use the two points and find the slope intercept form of the line then you can find a couple of x,y coordinates and graph it

slope = (8-3)/(-7-7) = -5/14
then y-3=-5/14(x-7)
y=-5/14x+11/2

2007-01-09 23:41:30 · answer #5 · answered by zzzfan14 3 · 0 0

you put (7,3) in quadrant 1 on the graph.
you put (-7,8) in quadrant 4 on the graph.

it makes a semi steep line going in
vvv & >>> direction (down and to the right)

2007-01-09 23:45:34 · answer #6 · answered by ? 2 · 0 0

browse google u will get the best answers

2007-01-09 23:38:44 · answer #7 · answered by rahima_as 2 · 0 0

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