What is the acceleration? What distance did he cover?

Question

A runner achieves a velocity of 11.1 m/s 9s after he begins.


Thank You.

Answer 1

acceleration is the rate of change of velocity in the certain point in time. so it is velocity over time. in your case acceleration will be 11.1/9 = 1.233333333 m/s2

Answer 2

V=A*t
X=.5*A*t^2

Answer 3

Vf=at+vi
11.1m/s=a(9s)
a=1.23m/s^2

Vf^2=2ad+vi^2
(11.1m/s)^2=2(1.23m/s^2)d
123.21m^2/s^2=(2.46m/s^2)d
d=50.1m