square root of 19 divided by square root of 40 ?
square root of 13 divided by square root of 5 ?
square root of 7 to the 4th power divided by square root of 12 to the 4th power?
please show the steps to getting the answers
2007-01-09 14:12:54 · 3 answers · asked by skittle8788 3 in Science & Mathematics ➔ Mathematics
sqrt19/(sqrt40)
40 = (2 * 2) * 2 * 5--> 2sqrt10, so:
sqrt19/(2*sqrt10)
now multiply top and bottom by sqrt10 (rationals not allowed on bottom)...
(sqrt10)*(sqrt19)/20
(sqrt190)/20
sqrt13/sqrt5
multiply top and bottom by sqrt5...
sqrt13*sqrt5 / 5
(sqrt65)/5
sqrt (7*7*7*7) / (sqrt 12 * 12 * 12 * 12)
since sqrt(7 * 7) = 7, that means it's 7*7, divided by 12*12
so that's 49/144
2007-01-09 14:23:25 · answer #1 · answered by car of boat 4 · 0⤊ 0⤋
(sqrt(19)/sqrt(40)) =
(sqrt(19) * sqrt(40))/40 =
(sqrt(760))/40 =
(sqrt(4 * 190))/40 =
(2sqrt(190))/40 =
sqrt(190)/20
----------------------------------------------
(sqrt(13)/sqrt(5)) = sqrt(65)/5
------------------------------------------------
(sqrt(7^4)/sqrt(12^4)) =
((7^4)^(1/2))/((12^4)^(1/2))
(7^(4 * (1/2)))/(12^(4 * (1/2)))
(7^2)/(12^2)
(49/144)
2007-01-09 22:36:44 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
4.35/6.32 0.68
3.6/2.2 1.63
2007-01-09 22:25:00 · answer #3 · answered by mouses_moyer 2 · 0⤊ 0⤋