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how do you multiply mixed numbers?

2007-01-09 14:07:44 · 5 answers · asked by Mayday Cay 2 in Science & Mathematics Mathematics

5 answers

convert each "mixed number" into a ratio of two integers
say a/b and c/d ..
multiply a/b * c/d = ac/bd

for example to multply 5 and 1/3 by 2 and 1/4
observe:
5 & 1/3 = 15/3 + 1/3 = 16/3

2 and 1/4 = 8/4 + 1/4 = 9/4

if we say 16/3 = a/b { a = 16, b = 3}

and 9/4 = c/d { c = 9, d = 4}

then the product
a/b * c/d = ac/bd = 16*9 / 3 * 4 = 144 / 12 = 12

to "check", multiply 5.33 * 2.25 = 11.99925 which apprx "12"

2007-01-09 14:11:38 · answer #1 · answered by atheistforthebirthofjesus 6 · 0 0

Turn the Mixed Numbers into Improper Fraction (4 and 1 over 2) by multiplying the whole number by the denominator (4 x 2) then add the numerator (4X2+1=9) and the denominator stays the same and you do the same thing with the other number the x and simplify as usual (numerator x numerator, denominator x denominator) and turn it back to a mixed fraction or whole number.

2007-01-10 21:12:46 · answer #2 · answered by ES-335 2 · 0 0

turn them into improper fractions and multiply them the way you do regular ones. like 2 1/2 (5 2/2) becomes 5/2 times 12/2 and 5/2 times 12/2( which is also 6) is 60/2 or 30. hope this helps.

2007-01-09 22:18:38 · answer #3 · answered by the_lovely_morena 2 · 0 0

Tranfer all fractions to decimals - multply and then transfer back

2007-01-09 22:12:57 · answer #4 · answered by geoffgilsey 3 · 0 0

(a b/c)(d e/f) =
((ac + b)/c)((df + e)/f) =
((ac + b)(df + e))/(cf)

if you have
(-a b/c)(d e/f) = -(a b/c)(d e/f)

if you have

(-a b/c)(-d e/f) = (a b/c)(d e/f)

if you have

(a b/c)(-d e/f) = -(a b/c)(d e/f)

2007-01-09 22:42:26 · answer #5 · answered by Sherman81 6 · 0 0

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