English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1) 7x/9 * 11/9x

2) 8d * 9/f

3) 30m2n/4m

2007-01-09 13:49:33 · 3 answers · asked by Aaron 3 in Science & Mathematics Mathematics

3 answers

1.7x/9*11/9x
=(7x *11)/9*9x
=77/81 (after cancelling x of numerator and denominator)
2.8d*9/f
=(8d*9)/f
=72d/f
3.30m2n/4m
=60mn/4m
=(60/4)(mn/m)
=15n
t

2007-01-09 14:31:20 · answer #1 · answered by alpha 7 · 0 0

1) group the top, then group the bottom
7x times 11, all that divided by (9x times 9)
that's 77x/81x
reduced to 77/81

2) that one's just 72d/f

3) 30m^2n/4m...
divide the 30 by 2, and cancel the m out:
15mn/2

(if that last one was m-squared)

2007-01-09 21:54:35 · answer #2 · answered by car of boat 4 · 0 0

if by this you mean

1.)
((7x)/9) * (11/(9x))
(77x)/(81x)
(77/81)

--------------------------------------

2.)
8d * (9/f)
(72d)/f

---------------------------

3.)
(30m^2n)/(4m)
(30/4) * m^(2 - 1) * n
(15/2) * mn
(15mn)/2

2007-01-09 23:24:12 · answer #3 · answered by Sherman81 6 · 0 0

fedest.com, questions and answers