2007-01-09 13:37:12 · 8 answers · asked by princessjanie3 1 in Science & Mathematics ➔ Mathematics
a^2 + b^2 = c^2
60^2 + 11^2 = c^2
3600 + 121 = c^2
3721 = c^2
61 = c
2007-01-09 13:42:21 · answer #1 · answered by Emily 3 · 1⤊ 0⤋
The Pythagorean Theorem:
a^2+b^2=c^2
60^2+11^2=c^2
c^2=3,721
c=61
The hypotenuse is 61.
2007-01-09 21:45:08 · answer #2 · answered by Anonymous · 0⤊ 0⤋
According to Pythagoras's Theorem
a^2+b^2=c^2 if a and b are sides and c is hypotenuse
c^2=60^2+11^2
c^2=3600+121
c^2=3721
c=61
2007-01-09 21:44:56 · answer #3 · answered by Anonymous · 1⤊ 0⤋
It's 61. Use a² + b² = c².
Here 60² = 3600 and 11² = 121.
So c² = 3721
and c = 61.
2007-01-09 21:48:24 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
60 squared + 11 squared = hypotenuse squared
60 squared = 3600
11 squared = 121
theremore
square root of 3600 + 121 = hypotenuse
square root of 3721
= 61
2007-01-09 21:43:45 · answer #5 · answered by Anonymous · 1⤊ 0⤋
60^2+11^2=hypotenuse^2
3600+121=h^2
3721=h^2
h=square root of 3721
2007-01-09 21:47:21 · answer #6 · answered by Anonymous · 0⤊ 0⤋
61
a²+b²=c²
60²+11²=c²
3600+121=c²
3721=c²
61=c
2007-01-09 21:39:50 · answer #7 · answered by aficionado210 2 · 1⤊ 0⤋
a^2 + b^2 = c^2
61
2007-01-09 21:41:56 · answer #8 · answered by EQ 6 · 1⤊ 0⤋