2007-01-09 13:36:15 · 6 answers · asked by tweetyman7 1 in Science & Mathematics ➔ Mathematics
Wrong Question????
2007-01-09 13:46:54 · answer #1 · answered by Ritesh13171 3 · 0⤊ 0⤋
It doesn't.
Calculus deals with differentiation, integration and other things involving infinitesimals. There, as in most math, 2-2 = 0 or, at the very least, is congruent to 0. Therefore, the answer of 0 over any non-zero denominator will be congruent to 0.
If you are in the Z5 field -- and there, I'd wonder why you are doing calculus -- then the calculation would be OK as 5 is congruent to 0.
In the cyclic group of order 5, the only operation allowed is the addition. In order to simulate subtraction, one has to find the additive inverse of a number. The additive inverse of 2 is 3. Adding 3 has the same result as subtracting 2.
A division would not make sense except that, in this case, since 2+4 is congruent to 1 and dividing by 1 is the same as not dividing at all, I guess we could survive.
So, you formula becomes:
(2+3)/1 = 2+3 = 5 (which is congruent to 0 in this group)
However, I would find it difficult to do calculus in that group.
2007-01-09 21:41:14 · answer #2 · answered by Raymond 7 · 0⤊ 0⤋
Is not right. First, 2-2 = 0. Then, 0/6=0.
2007-01-09 21:41:14 · answer #3 · answered by roxifoxiv 3 · 0⤊ 0⤋
It doesn't!! Numerator: 2-2 = 0.
Denominator: 2 + 4 = 6.
0/6 = 0.
2007-01-09 21:42:22 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
x/6 = 5 therefore the numerator must equal 30, since it doesn't (2-2 = 0) there is a problem with the question.
2007-01-09 21:45:58 · answer #5 · answered by car 3 · 0⤊ 0⤋
(2-2) = 0
(2+4) = 6
0/6 = 0
You should reconsider whose homework you copy.
2007-01-09 21:44:44 · answer #6 · answered by shwin_nugin 2 · 0⤊ 0⤋