When you reverse my digits a larger number is formed, the product of me and my new number is 65,125. What number am I??
2007-01-09 13:12:23 · 5 answers · asked by :] 2 in Science & Mathematics ➔ Mathematics
Figure the prime factors of 65,125:
65,125 / 5 = 13,025
13,025 / 5 = 2,605
2,605 / 5 = 521
521
So you have 5 x 5 x 5 x 521
521 is prime and is three digits. The other numbers (5 x 5 x 5) = 125, so there you have your answer.
I am 125.
When you reverse me, the larger number 521 is formed. The product is 65,125.
125 x 521 = 65,125
2007-01-09 13:20:25 · answer #1 · answered by Puzzling 7 · 2⤊ 0⤋
The original number would be 125 and the reverse of that number is 521
125*521=65 125
2007-01-09 13:20:29 · answer #2 · answered by Anonymous · 0⤊ 0⤋
abc x cba = 65,125 and c > a
sqrt of 65,125 is 255, so abc is less than 255
65,125 factors into 5 x 5 x 5 x 521
125 x 521 = 65,125 therefore abc =125
2007-01-09 13:23:20 · answer #3 · answered by xaviar_onasis 5 · 0⤊ 0⤋
621
2007-01-09 13:20:47 · answer #4 · answered by blackbeauty 2 · 0⤊ 0⤋
You're 125
2007-01-09 14:08:26 · answer #5 · answered by ntt335 1 · 0⤊ 0⤋