Algebra Question?

Question

How do you simplify root 1/18 (radical)?

Answer 1

first multiply both the top and bottom by root 18, to get rid of the radical on the bottom, so you get
sqrt(18)/(sqrt(18)*sqrt(18)) = sqrt(18)/18.

next simplify the sqrt(18). factor into primes:
18 = 3*3*2
since 3 is in there twice, you can take the square root of 3^2 out, which gives you 3*sqrt(2). nothing you can do with the 2.

now you have 3*sqrt(2)/18, and 3/18 simplifies to 1/6. so the final answer is sqrt(2)/6

Answer 2

Well, you could say that ROOT(1/18) is the same as
ROOT(1/(2*9)) since 2*9 is 18.

Taking the 9 out, you get

1/3ROOT(1/2)

or

1
------
3ROOT(2)

Answer 3

1/3root(2)
multiply to and bottom by root(2), because you cannot have root in the denominator
final answer would be
root(2)/6

Answer 4

sqrt(1/18)

= sqrt(1) / sqrt(18)

Now multiply the numerator and denominator by sqrt(18) to get a rational denominator:
= sqrt(1) * sqrt(18) / [sqrt(18) * sqrt(18)]

The numerator becomes sqrt(18) and the denominator becomes 18.

So the final answer is:
sqrt(18) / 18

Answer 5

sqrt(1/18) = 1/sqrt(18)

And sqrt(18) = sqrt(9)*sqrt(2) = 3*sqrt(2)

So:

sqrt(1/18) = 1/sqrt(18) = 1/(3*sqrt(2))

Hope this helped!

=)