if a blue eyed man marries a brown eyed woman whose father was blue eyed, what is the genotype and phenotype?

Question

also what is the phenotype and genotype of the offspring

brown eys are usually dominant over blue eyes

heteorozygous

Answer 1

The man's genotype will be: bb
The womans genotype will be: Bb
The man's Phenotype is Blue and the womans is brown.

Thier offspring will have a 50% chance to have Brown eyes with the genotype Bb, and a 50% chance to have blue eyes with the genotype bb

Answer 2

this is dependant upon whether or not you are observing purely Mendelian genetic traits. If so, the Brown eyed woman would have a gene for blue and a gene for brown eyes. The brown eye gene would be expressed while the blue eye gene would not be obvious. Her blue eye gene could be passed on to her offspring (50% chance per each child) and be seen as her blue eyed mate would have only blue eyed genes.
All her brown eyed children would have one brown eye gene and one blue eye gene.
All her blue eyed children would have two blue eyed genes and no brown eyed genes.

Answer 3

the colour blind father is heterozygous for brown eyes as a results of fact his mom had blue eyes. So he's Bb. as a results of fact he's male, he intercourse chromosomes are XY. The gene for coloration blindness is on the x chromosome so he's XcY the mummy is has blue eyes so she is bb for eye coloration. Being female her intercourse chromosomes are XX. Her father replaced into coloration blind so the X chromosome he gave her could have the gene for coloration blindness on it. She isn't coloration blind as a results of fact she has yet another X chromosome it is ordinary. She is a service for colourblindness she would be in a position to be XcX. Father Bb and XcY mom bb and XcX The Phenotypes and genotypes of the attainable babies are Phenotype: Brown eyed coloration blind son. Genotype: Bb XcY Phenotype: Brown eyed coloration blind daughter Genotype: Bb XcXc Phenotype: Brown eyed ordinary imaginative and prescient daughter Genotype: Bb XcX (a service) Phenotype: Blue eyed coloration blind son: Genotype: bb XcY Phenotype: Blue eyed coloration blind daughter Genotype: bb XcXc Phenotype: Blue eyed ordinary imaginative and prescient daughter Genotype: bb XcX (a service) there's a 50% threat that the offspring could have blue eyes and 50% threat they are going to be brown. there is likewise 50/50 threat of being male of female. ALL sons (one hundred%) would be coloration blind. 50% of daughters would be coloration blind and 50% could have ordinary imaginative and prescient (yet would be distributors) Edit (correction) Goodness - i'm very sorry :( you're truthfully suitable. there is relatively a 50/50 threat of the sons being coloration blind. this means that there is two extra attainable genotypes/ phenotypes to be extra to my checklist... Phenotype: Brown eyed ordinary imaginative and prescient son. Genotype: Bb XY Phenotype: Blue eyed ordinary imaginative and prescient son. Genotype: bb XY

Answer 4

Depends. I need the dominant and recessive traits. Also, is one or both homozygous/heterozygous for their traits? There isn't enough info.