Need help with this Algebra 2 problem!?

Question

Composite Funtion:

Find the first four iterations of each function, given the initial value.
f(1)=2, f(n)=3f(n-1)

I dont understand:
f(1)=3f(?-1)

I need to find what zero is first right? If so, how do I find zero?

Thank you all that helped so much! I definitely understand it now.

Answer 1

go to www.cosmeo.com. it is a real help.

Answer 2

If f(1) = 2, then f(2) = 3 f(1) = 6, and f(3) = 3 f(2) = 18. It is evident that f(n) = 2(3)^(n-1). This has no zeroes for any real n.

Answer 3

f(1) = 2
f(n) = 3f(n-1)
if n =2, then f(2) = 3f(2-1) = 3f(1) = 3(2) = 6
if n=3 then f(3) = 3f(3-1) = 3f(2) = 3(6) = 18
if n=4 then f(4) = 3f(4-1) = 3f(3) = 3(18) = 52
This should be the answer

Answer 4

f(1) = 2

given f(n) = 3f(n-1)

So let n = 2

f(2) = 3f(2-1) = 3f(1) = 3 * 2 = 6

all you need is to find f(2), f(3), f(4), f(5). Don't worry about f(0) because it is not even defined.

Answer 5

f(2)= 3*f(1)= 3*2=6
f(3)= 3*f(2)= 3*6=18
f(4)= 54

Answer 6

im cant get this eather!!!